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若存储器的容量为512K × 8位，则地址代码有（）位？

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若存储器的容量为512K×8位，则地址代码有（）位？

答案解析有点问题，512k，1k=1024，512x1024x8=4M，这是存储容量的大小，至于存储位数应该是512×1024=2^19，所以地址是19位
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